1 . | Answer : Option D | Explanation : | 50% of ($86.8º\over360º$x30000)=$50\over100$x5400=2700 | | | 2 . | Answer : Option A | Explanation : | 60% of ($86º.4º\over360º$x40000]=$60\over100$x9600=5760 | | | 3 . | Answer : Option B | Explanation : | Total=$30000\over360°x100$[54° × 40 + 90° × 55 + 64.8° × 50 + 50.4° × 60 + 43.2° × 45 + 57.6° × 60] =$360000\over360°x100$[2160 + 4950 + 3240 + 1944 +3456] ==$30000\over36000$x18774=15645 | | | 4 . | Answer : Option B | Explanation : | Total boys = 4000 + 4800 + 1800 + 1600 + 2880 + 5760 =20840 Total girls = 40000 - 20840 = 19160 Diff = 20840 - 19160 = 1680
| | | 5 . | Answer : Option B | Explanation : | | | | 6 . | Answer : Option B | Explanation : | Total males = 120, Females(one cate) = 20 + 12 + 25 = 57 Diff = 120 - 57 = 63 | | | 7 . | Answer : Option C | Explanation : | M + F = 15, F = 8 M = 7, Ratio = 15 : 7
| | | 8 . | Answer : Option D | Explanation : | Total males = 40 + 18 + 25 + 15 + 7 + 7 = 112 | | | 9 . | Answer : Option A | Explanation : | Female (total) = 80, Male (alt-3 cate) = 10 - 2 = 8
%=$8\over80$x100=10% | | | 10 . | Answer : Option B | Explanation : | | | | |
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