| **Answers & Solutions ** | | 1 . | Answer : Option D | Explanation : | Choices 1, 2 and 4 can be easily ruled out. 3 may be an assumption because this may be the reason of price difference. But it is also possible that the cost of bottling abroad may itself be higher. Hence go for 5. This is why the author suggests the way out of “embarrassment” | | | 2 . | Answer : Option D | Explanation : | Let us make a table as shown below and put the information obtained from the clues 4 and 5 in the table. It looks as follow:
Now from clue 1, we get that D and I get in at the same station where G and H get down. obviously D and I did not get in at base station or station I or III or V. Thus, D and I must have got in either at station II or at station IV. But it is given that H travels between only two stations, hence we can conclude that G and H did not get down at station IV also. Hence, D and I get in at station II and G and H get down at station II.Also, we get that H gets in at station I. Now, from clue 2, we get that C gets down before G. This implies that C gets down at station I. Again, from clue 3, we get that B and F get in before D. This implies that B and F get in at base station. Again, from clue 3, we get that B and F get down at next station after D. This implies that, B and F did not get down at station VI (because no person gets down at station V). And since D gets in at station II, this implies that B and F must have got down after at least station III. Thus, we can conclude that B and F get down at station IV and D gets down at station III. Again, from clue 2, we get that C gets down at station I before G. This implies that C must have got in at the base station. Also, we get that A and E must have got in either at station IV or at station V. Hence, we can conclude that J gets in at base station (see clue 4) and get down at station I Hence, by elimination, we get that A and E get down at station VI. But still we do not where I gets down among the stations III, IV and VI. Thus the whole information obtained can be summarised as below
| | | 3 . | Answer : Option C | Explanation : | Let us make a table as shown below and put the information obtained from the clues 4 and 5 in the table. It looks as follow:
Now from clue 1, we get that D and I get in at the same station where G and H get down. obviously D and I did not get in at base station or station I or III or V. Thus, D and I must have got in either at station II or at station IV. But it is given that H travels between only two stations, hence we can conclude that G and H did not get down at station IV also. Hence, D and I get in at station II and G and H get down at station II.Also, we get that H gets in at station I. Now, from clue 2, we get that C gets down before G. This implies that C gets down at station I. Again, from clue 3, we get that B and F get in before D. This implies that B and F get in at base station. Again, from clue 3, we get that B and F get down at next station after D. This implies that, B and F did not get down at station VI (because no person gets down at station V). And since D gets in at station II, this implies that B and F must have got down after at least station III. Thus, we can conclude that B and F get down at station IV and D gets down at station III. Again, from clue 2, we get that C gets down at station I before G. This implies that C must have got in at the base station. Also, we get that A and E must have got in either at station IV or at station V. Hence, we can conclude that J gets in at base station (see clue 4) and get down at station I Hence, by elimination, we get that A and E get down at station VI. But still we do not where I gets down among the stations III, IV and VI. Thus the whole information obtained can be summarised as below
| | | 4 . | Answer : Option B | Explanation : | Let us make a table as shown below and put the information obtained from the clues 4 and 5 in the table. It looks as follow:
Now from clue 1, we get that D and I get in at the same station where G and H get down. obviously D and I did not get in at base station or station I or III or V. Thus, D and I must have got in either at station II or at station IV. But it is given that H travels between only two stations, hence we can conclude that G and H did not get down at station IV also. Hence, D and I get in at station II and G and H get down at station II.Also, we get that H gets in at station I. Now, from clue 2, we get that C gets down before G. This implies that C gets down at station I. Again, from clue 3, we get that B and F get in before D. This implies that B and F get in at base station. Again, from clue 3, we get that B and F get down at next station after D. This implies that, B and F did not get down at station VI (because no person gets down at station V). And since D gets in at station II, this implies that B and F must have got down after at least station III. Thus, we can conclude that B and F get down at station IV and D gets down at station III. Again, from clue 2, we get that C gets down at station I before G. This implies that C must have got in at the base station. Also, we get that A and E must have got in either at station IV or at station V. Hence, we can conclude that J gets in at base station (see clue 4) and get down at station I Hence, by elimination, we get that A and E get down at station VI. But still we do not where I gets down among the stations III, IV and VI. Thus the whole information obtained can be summarised as below
| | | 5 . | Answer : Option C | Explanation : | Let us make a table as shown below and put the information obtained from the clues 4 and 5 in the table. It looks as follow:
Now from clue 1, we get that D and I get in at the same station where G and H get down. obviously D and I did not get in at base station or station I or III or V. Thus, D and I must have got in either at station II or at station IV. But it is given that H travels between only two stations, hence we can conclude that G and H did not get down at station IV also. Hence, D and I get in at station II and G and H get down at station II.Also, we get that H gets in at station I. Now, from clue 2, we get that C gets down before G. This implies that C gets down at station I. Again, from clue 3, we get that B and F get in before D. This implies that B and F get in at base station. Again, from clue 3, we get that B and F get down at next station after D. This implies that, B and F did not get down at station VI (because no person gets down at station V). And since D gets in at station II, this implies that B and F must have got down after at least station III. Thus, we can conclude that B and F get down at station IV and D gets down at station III. Again, from clue 2, we get that C gets down at station I before G. This implies that C must have got in at the base station. Also, we get that A and E must have got in either at station IV or at station V. Hence, we can conclude that J gets in at base station (see clue 4) and get down at station I Hence, by elimination, we get that A and E get down at station VI. But still we do not where I gets down among the stations III, IV and VI. Thus the whole information obtained can be summarised as below
| | | 6 . | Answer : Option D | Explanation : | Let us make a table as shown below and put the information obtained from the clues 4 and 5 in the table. It looks as follow:
Now from clue 1, we get that D and I get in at the same station where G and H get down. obviously D and I did not get in at base station or station I or III or V. Thus, D and I must have got in either at station II or at station IV. But it is given that H travels between only two stations, hence we can conclude that G and H did not get down at station IV also. Hence, D and I get in at station II and G and H get down at station II.Also, we get that H gets in at station I. Now, from clue 2, we get that C gets down before G. This implies that C gets down at station I. Again, from clue 3, we get that B and F get in before D. This implies that B and F get in at base station. Again, from clue 3, we get that B and F get down at next station after D. This implies that, B and F did not get down at station VI (because no person gets down at station V). And since D gets in at station II, this implies that B and F must have got down after at least station III. Thus, we can conclude that B and F get down at station IV and D gets down at station III. Again, from clue 2, we get that C gets down at station I before G. This implies that C must have got in at the base station. Also, we get that A and E must have got in either at station IV or at station V. Hence, we can conclude that J gets in at base station (see clue 4) and get down at station I Hence, by elimination, we get that A and E get down at station VI. But still we do not where I gets down among the stations III, IV and VI. Thus the whole information obtained can be summarised as below
| | | 7 . | Answer : Option D | Explanation : | The position of the sun is not known. | | | 8 . | Answer : Option D | Explanation : | The information regarding weightage of all the papers is not known. | | | 9 . | Answer : Option D | Explanation : | If different shapes have the same area, their perimeters are different. Hence, amounts of fencing will not be equal | | | 10 . | Answer : Option D | Explanation : | From I and II:Follow the process as given below: Suppose number of 1-point markers be x; and the number of 2-point markers be y.
Now, according to the question,
we get
x + y = 60 ....(i)
and x + 2y = 83 .... (ii)
? x = 37 and y = 23.
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