#
SBI PO Quantitative aptitude practice set 26

IBPS Online
April 01, 2017
Quantitative Aptitude

| | | 1 . | A 380-metre-long train running at a speed of 80 kmph will take how much time to cross another 420-metrelong train running in opposite direction at a speed of 48 kmph? |
A. 20.12 seconds | B. 22.5 seconds | C. 20.5 seconds | D. 18.57 seconds | | | 2 . | How many kilograms, of sugar at Rs.42 per kg should a man mix with another 25 kg of sugar at Rs.28 per kg so that he may gain 25% profit by selling Rs.40 per kg? |
A. 8 kg | B. 15 kg | C. 20 kg | D. 10 kg | | | 3 . | A number X is increased by 20% to get another number Y. A third number Z is obtained by increasing Y by 10%. By what per cent should Z be decreased to get X? |
A. 26.51% | B. 24.24% | C. 28.36% | D. 31.71% | | | 4 . | Z can do a piece of work in 42 days. Y can do the same piece of work in 36 days. W can do it in 56 days. Z worked for 18 days and handed it to Y, who worked for 9 days and left the job for W. How many days will W take to finish the work? |
A. 16 days | B. 20 days | C. 24 days | D. 18 days | | | 5 . | Munsi Premchand sold a cow at a loss of 15%. Had he sold it for `300 more he would have earned a profit of 10% instead of loss. Find the cost price of the cow. |
A. 1200 | B. 1250 | C. 1100 | D. 1400 | | | | |

| **Answers & Solutions ** | | 1 . | Answer : Option C | Explanation : | Reqd time = $Length of train A + Length of train Bover Speed of train A + Speed of train B$
= $800 times 18 over 128 times 5$
= 22.5 seconds | | | 2 . | Answer : Option D | Explanation : | Selling price of 1 kg mixture = Rs.40 per kg profit = 25%
Cost price of 1 kg mixture = 40 x $100 over 125$ = Rs. 32 per kg
| | | 3 . | Answer : Option B | Explanation : | y = $x$ x $120 \over 100$ = $6x\over 5$
z = y x $110\over 900$ = $11y\over 10$
= $11 \over 10$ x $6\over 5$$x$ = $66 \over 55$$x$
Reqd % = ${66 \over 50}x - x \over {66\over 50}x$ x 100
= 24.24 % | | | 4 . | Answer : Option D | Explanation : | Work of Z in 1 day = $1\over 42$
Work of Z in 18 days = $18 \over 42$ = $3 \over 7$
Work of Y in 1 day = $1\over 36$
Work of Y in 9 days = $9\over 36$ = $1\over 4$
Work of W in 1 day = $1\over 56$
Remaining work = 1 - ($3\over 7$ + $1 \over 4$)
= $28 - (12 + 7) \over 28$
= $9 \over 28$
Now , W will take 56 x $9 \over 28$ = 18 days to finish the work. | | | 5 . | Answer : Option A | Explanation : | Let the cost price of cow be Rs. X
Selling price at 15 % loss = $x$ x $85 \over 100$
x = $300 \times 100 \over 25$
= Rs.1200 | | | | |

## 0 comments:

## Post a Comment