## Friday, 31 March 2017

1 . Directions (1-5): Study the following table carefully to answer the questions that follow.

Total number of students studying in various colleges over the years $Q.$ What is the ratio of the number of students studying in College A to the number of students studying in College E in the year 2012?

 A.   15 : 14 B.   7 : 8 C.   9 : 8 D.   10 : 11
2 . What is the difference between the average number of students studying in College A over the given period and the average number of students studying in College C over the same period?

 A.   23 B.   128 C.   120 D.   20
3 . What is the difference between the total number of students studying in College B over the given period and the total number of students studying in College D over the same period?

 A.   218 B.   35 C.   32 D.   212
4 . What is the average number of students studying in College E over the given period?

 A.   928 B.   930 C.   933 D.   980
5 . The number of students studying in College C in the year 2010 is approximately what per cent of the total number of students studying in various colleges in that year?

 A.   20 B.   23 C.   17 D.   25
6 . What compound interest can be obtained on an amount of `3980 after 2 years at the rate of 8 per cent per annum? (Calculate the approximate value.)

 A.   650 B.   680 C.   600 D.   665
7 . If $a\over 6$ = $b\over 10$ = $c\over 4$ , then $a + b + c \over c$ = ?

 A.   $1\over 4$ B.   $3\over 5$ C.   2 D.   5
8 . If 7x + 8y = 53 and 5x + 12y = 63, then what is the value of (y – x)?

 A.   -2 B.   2 C.   1 D.   -1
9 . A man walks at a speed of 5 kmph and runs at a speed of 10 kmph. How much time will the man take to cover a distance of 28 km, if he covers half of his journey walking and half of his journey running?

 A.   8.4 hours B.   6 hours C.   5 hours D.   4.2 hours
10 . A, B, C and D are four consecutive numbers. If the sum of A and D is 103, what is the product of B and C?

 A.   2652 B.   2562 C.   2970 D.   2550

1 .
 Answer : Option B Explanation : Reqd ratio = $980 over 1120$ = $7over 8$ = 7 : 8
2 .
 Answer : Option D Explanation : Average no.of students in college A = $5610 \over 6$ = 935 Average no.of students in college C = $5490 \over 6$ = 915 Reqd difference = 935 - 915 = 20
3 .
 Answer : Option D Explanation : Total number of students in College B = 5810 Total number of students in College D = 5598Reqd difference = 5810 – 5598 = 212
4 .
 Answer : Option D Explanation : Average no.of students in College E = $5880\over 6$ = 980
5 .
 Answer : Option A Explanation :
6 .
 Answer : Option D Explanation : For 2 years CI at 8%= 8 + 8 + $8 \times 8 \over 100$= 16.64%CI = 3980 x $16.64 \over 100$ = 662.2 $\cong$ $665$
7 .
 Answer : Option D Explanation : $a\over 6$ = $b\over 10$ = $c\over 4$ = 1a = 6k , b = 10k, c = 4k$a + b + c \over c$ = $(6 + 10 + 4)k\over 4k$ = 5
8 .
 Answer : Option C Explanation : 7x + 8y = 53 ... (i)5x + 12y = 63 ... (ii)On solving the equations, we getx = 3, y = 4y – x = 4 – 3 = 1
9 .
 Answer : Option D Explanation : Time = $14 \over 5$ + $14 \over 10$ = $42 \over 10$h = 4.2h
10 .
 Answer : Option A Explanation : Let the numbers be x, (x + 1), (x + 2) and (x + 3).Then, x + (x + 3) = 103or, x = 50Hence, product of B and C= (50 + 1) (50 + 2) = 51 × 52 = 2652