1)A person covers a certain distance at 7kmph .How many meters does he cover in

2 minutes.

A) 14 kmph B) 7 kmph C) 2400m D) 1200m**Answer:** Option C**Explanation:**Speed=72kmph=72*5/18 = 20m/s

Distance covered in 2min =20*2*60 = 2400m

2)If a man runs at 3m/s. How many km does he run in 1hr 40min

A) 18 km B) 7 km C) 12 km D) 17 km**Answer**: Option A**Explanation**:

Speed of the man = 3*18/5 kmph = 54/5kmph

Distance covered in 5/3 hrs=54/5*5/3 = 18km

3)A train covers a distance in 50 min ,if it runs at a speed of 48kmph on an average.The

speed at which the train must run to reduce the time of journey to 40min will be.

A) 18 kmph B) 60 kmph C) 30 kmph D) 50 kmph**Answer**: Option B

**Explanation:**

Time=50/60 hr=5/6hr

Speed=48mph

distance=S*T=48*5/6=40km

time=40/60hr=2/3hr

New speed = 40* 3/2 kmph= 60kmph

4) Vikas can cover a distance in 1hr 24min by covering 2/3 of the distance at 4 kmph and

the rest at 5kmph.the total distance is?

A) 18 km B) 6 km C) 12 kmD) 17 km**Answer:** Option B**Explanation**:

Let total distance be S

total time=1hr24min

A to T :: speed=4kmph

diistance=2/3S

T to S :: speed=5km

distance=1-2/3S=1/3S

21/15 hr=2/3 S/4 + 1/3s /5

84=14/3S*3

S=84*3/14*3 = 6km

5)walking at ¾ of his usual speed ,a man is late by 2 ½ hr. the usual time is.

A) 4 B) 7 ½ C) 7 D) 5**Answer:** Option B**Explanation:**

Usual speed = S

Usual time = T

Distance = D

New Speed is ¾ S

New time is 4/3 T

4/3 T – T = 5/2

T=15/2 = 7 ½

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